quiz6
You are given a 9.0Volt battery (negligible internal resistance), and three resistors 1.00Ohms, 2.00Ohms, and 3.00Ohms. These four items are all used in a closed circuit and arranged to draw the smallest current from the battery. The currents (listed as I(1), I(2), and I(3) are:
a)
I(1)=I(2)=I(3)=1.5Amps
b)
I(1)=I(2)=I(3)=0.25Amps
c)
I(1)=2.0*I(2)=3.0*I(3)=3.0Amps
d)
3.0*I(1)=2.0*I(2)=I(3)=5.5Amps
e)
I(1)=I(2)=I(3)=3.0Amps
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Now, the three resistors from problem 1 are placed in series with the battery. The electric potential drop across the 3.00Ohm resistor is:
a)
0.75 Volts
b)
1.5 Volts
c)
3.0 Volts
d)
4.5 Volts
e)
5.5 Volts
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Take the same three resistors and use all of them in a closed circuit with the battery. This time design the circuit to draw the most current from the battery. The total current drawn and the current through the 3.00Ohm resistor are (respectively, total is first #):
a)
0.25 Amps and 16.5 Amps
b)
3.0 Amps and 0.25 Amps
c)
16.5 Amps and 5.5 Amps
d)
5.5 Amps and 0.25 Amps
e)
16.5 Amps and 3.0 Amps
No answer given yet