Sample Test1 Answers

1.    e             2.      Test charge moves perpendicular to field, so along equipotential W=0.
3.    a
4.    Change in PE=4.5E9J
5.    Chane in electric Potential=2.85Volts
6.     a)    q1=1.05E-4C         q2=2.11E-4C
b)    F(new)=2.00N
c)    PE=-e(V[total])=-9.07E-13J
d)      V[total]=5.67E6 Volts

7.    a)    F=0.01N in negative x direction
b)    Same field, Same force
c)    Change in PE=0
d)    x=94.87m

8.    a)    V=3.6E5Volts
b)    V=1.8E6 Volts
c)    W=1.08J
d)    W=5.4J
e)W=4.32J

9.    a)    A=1.13E7m^2
b)    Q=5.00C
c)    W=12.5J
d)    W=2.5J